Consider the following reaction: 2 no(g) + br2(g) ⇄ 2 nobr(g) kp = 27 at 25°c what is the value of kc at 25°c?

a) 1.1
b) 13
c) 27
d) 55
e) 660

The value of Kc is 660 (Option E) is correct

Explanation:

Step 1: Data given

Kp = 27

Temperature = 25.0 °C

Step 2: The balanced equation

2 NO(g) + Br2(g) ⇄ 2 NOBr(g)

Step 3: Calculate Kc

Kp = Kc * (RT)^Δn

⇒ with Kp = 27

⇒ with Kc = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = The temperature = 25 °C = 298 K

⇒ Δn = the difference in moles = -1

27 = Kc * (0.08206*298)^-1

Kc = 660

The value of Kc is 660 (Option E) is correct