Calculate the force of attraction between a ca 2 ( 2 charge) ion and an o-2 (-2 charge) ion whose centers are separated by a distance of 1.25nm. use "e" for an exponent of power 10.

F = -5.91 E-10 N

Explanation:

The force of attraction between the ions Ca²⁺ and O²⁻ is given by the Coulomb's Law:

where K: is the Coulomb's constant, q₁ and q₂: are the charges of the electrons (e = 1.602E-19 C) of the ions, and r: is the distance between the charges.      

With q₁ = charge of Ca = (2+)(1.602E-19 C), q₂ = charge of O = (2-)(1.602E-19 C), K= 9E09 N.m².C⁻² and r = 1.25nm = 1.25 E-09 m, the force of attraction between the ions is:

Therefore, the force of attraction between a Ca²⁺ ion and O²⁻ ion is -5.91 E-10 N.

I hope it helps you!  

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