If it takes 10.0 kj of heat to raise the temperature of 100.0g if a substance by 50°c, what is the specific heat of the substance?

2.0 J/g°C

Explanation:

We are given;

We are required to calculate the specific heat capacity of the substance;

Quantity of heat = Mass × specific heat × change in temperature

That is;

Q = mcΔT

Rearranging the formula;

c = Q ÷ mΔT

Therefore;

c = 10000 J ÷ (100.0 g × 50°C)

  = 2.0 J/g°C

Thus, the specific heat of the substance is 2.0 J/g°C

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