The total pressure inside a 1.43l cylinder at 28 degrees is 1.03 atm. if the temperature drops to -35 degrees, and the volume remains the same, what is the new temperature inside the cylinder?

0.81 atm will be the new pressure.

Explanation:

This is the formula to solve this:

P₁ / T₁ = P₂ / T₂

1.03 atm / (28°C + 273) = P₂ / (-35°C + 273)

1.03 atm / 301K = P₂ / 238K

(1.03 atm / 301K) . 238K = 0.81 atm

The gas pressure is directly proportional to its absolute temperature when the volume keeps on constant.

The new pressure at the new temperature 238 K, is 0.814 atm

Explanation:

Step 1: Data given

Volume = 1.43 L

Temperature = 28°C

Total pressure = 1.03 atm

The temperature drops to -35 °C

The volume stays constant ( = 1.43 L)

Step 2: Calculate the new pressure

P1/T1 = P2/T2

⇒ with P1 = The initial pressure = 1.03 atm

⇒ with T1 = the initial temperature = 28 °C = 301 K

⇒ with P2 = The final pressure = ?

⇒ with T2 = The final temperatures = -35 °C = 238 K

1.03 / 301  = P2 / 238

P2 = (1.03*238)/301

P2 = 0.814 atm

The new pressure at the new temperature 238 K, is 0.814 atm

where is the following

explanation:

im not exactly sure but i think its b!