Calculate to three significant digits the density of dinitrogen monoxide gas at exactly and exactly . you can assume dinitrogen monoxide gas behaves as an ideal gas under these conditions.

see explanation below

Explanation:

You miss the part of the temperature and pressure. According to what I found this is held under 30 °C (or 303 K) and 1 atm.

The problem states that we can treat this gas as an ideal gas, therefore, we can use the equation of an ideal gas which is:

PV = nRT (1)

Now, the density (d) is calculated as:

d = m/V (2)

We can rewrite (2) in function of mass of volume so:

m = d*V (3)

Now, the moles (n) of (1) can be calculated like this:

n = m /MM (4)

If we replace it in (1) and then, (3) into this we have the following:

PV = mRT/MM > replacing (3):

PV = dVRT/MM > V cancels out so finallly:

P = dRT/MM

d = P * MM / RT (5)

The molar mass of N2O is 44 g/mol So, replacing all the data we have:

d = 1 * 44 / 0.082 * 303

d = 1.77 g/L

the answer would be b i believe

a electronegativity decreases beacuse the size of nucleus is bigger.