Apharmacy intern is asked to prepare 3 l of a 30% w/v solution. t he pharmacy stocks the active ingredient in 8-ounce bottles of 70% w/v strength. how many bottles will be needed as the source of the active ingredient?

The number of bottles that will be needed are 6

Explanation:

We are given:

Amount of solution, the intern is asked to prepare = 3 L = 3000 mL   (Conversion factor:  1 L = 1000 mL)

Strength of solution needed = 30 % (w/v)

This means that in 100 mL of solution, the solute present is 30 grams

So, in 3000 mL of solution, the solute present will be =

Active ingredient present in 1 bottle = 8 ounce of 70 % (w/v)

Conversion factor used: 1 ounce = 29.57 mL

So,

Amount of active ingredient present in 1 bottle =

To calculate the number of bottles, we need to divide the total amount of solution needed by the amount of active ingredient present in 1 bottle, we get:

Putting values in above equation, we get:

Hence, the number of bottles that will be needed are 6

the answer for sodium is 0.186

the answer for rubidium is 0.251

im doing test rn im going with 2 but ill give answer if itss wrong,   : )