Assuming that all the h comes from hcl, how many grams of sodium hydrogen carbonate will totally neutralize the stomach acid?

The question is incomplete, here is the complete question:

Assuming that all the comes from HCl, how many grams of sodium hydrogen carbonate will totally neutralize the stomach acid? Volume = 500 mL pH= 2

The mass of sodium hydrogen carbonate needed to completely neutralize stomach acid is 0.42 grams

Explanation:

To calculate the hydrogen ion concentration of the solution, we use the equation:

We are given:

pH = 2

Putting values in above equation, we get:

Molarity of hydrogen ions = 0.01 M

Volume of solution = 500 mL = 0.5 L   (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

The chemical equation for the reaction of HCl and sodium hydrogen carbonate follows:

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of sodium hydrogen carbonate

So, 0.005 moles of HCl will react with = of sodium hydrogen carbonate

Moles of sodium hydrogen carbonate = 0.005 moles

Molar mass of sodium hydrogen carbonate = 84 g/mol

Putting values in above equation, we get:

Hence, the mass of sodium hydrogen carbonate needed to completely neutralize stomach acid is 0.42 grams