1) if 0.193 grams of toluene is dissolved in 2.532 grams of p-xylene, what is the molality of toluene in the solution? 2) if a freezing point depression of 3.57°celcius is measured for the solution described in question 1, calculate for p-xylene.3) suppose you dissolved 0.123 gram of pentane in 2.493 grams of p-xylene and measured a freezing point depression of 2.88°celcius for the solution. calculate the molar mass of pentane using this data and the value for that you calculated in question 2.

The value of for xylene is 4.309°C/m.

The molar mass of pentane using this data is 73.82 g/mol.

Explanation:

where,

=depression in freezing point

= freezing point constant  

we have :

1) freezing point constant  for xylene = =?

Mass of toluene = 0.193 g

Mass of xylene = 2.532 kg = 0.002532 kg ( 1 g =0.001 kg)

The value of for xylene is 4.309°C/m.

2)

Mass of pentane = 0.123 g

molar mass of pentame= M

Mass of xylene = 2.493 g =  0.002493 kg

Freezing point Constant of xylene =

M = 73.82 g/mol

The molar mass of pentane using this data is 73.82 g/mol.