The freezing point of an aqueous solution containing an unknown solute is -2.60 degc. the solution was prepared by dissolving 5.00 g of a nonelectrolytic solute in 100. ml of water. what is the molar mass of the unknown solute?

The molar mass of the unknown solute is 35.8 g/mol

Explanation:

Depression in freezing point is given by:

= Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

= freezing point constant =

m= molality

Weight of solvent (water)=      (1kg=1000g)

Molar mass of unknown non electrolyte = M g/mol

Mass of unknown non electrolyte added = 5.00 g

The molar mass of the unknown solute is 35.8 g/mol

a is the answer to this question

explanation:

b. examine and describe cells