Using this information together with the standard enthalpies of formation of o2(g), co2(g), and h2o(l) from appendix c, calculate the standard enthalpy of formation of acetone.
complete combustion of 1 mol of acetone (c3h6o) liberates 1790 kj:
c3h6o(l)+4o2(g)? 3co2(g)+3h2o(l)? h? =? 1790kj

Ibelieve the answer is d

Answer:             1.0  × 10⁻⁵ msolution:                     as we know ph is given as,                                    ph  = -log [h⁺]and,                                    [h⁺]  =  10^-ph    (1)putting value of ph in eq. 1,                                    [h⁺]  =  10⁻⁵                                    [h⁺]  =  1.0  × 10⁻⁵ m