The molecular weight of calcium carbonate, caco3, is 100.09 3.
mol
how many moles of calcium carbonate are in 63.8 g of calcium carbonate?
express the answer using 3 significant figures.

Number of Moles = Reacting mass / Molecular mass

                              = 63.8 / 100.09

                              = 0.637g

Hence, the moles of calcium carbonate  in 63.8 g of calcium carbonate is 0.637g

Explanation:

lol idk man i guess u gotta ask bill nye the science guy

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i think? ?