A32.00 ml sample of an unknown h3po4 solution is titrated with a 0.110 m naoh solution. the equivalence point is reached when 24.83 ml of naoh solution is added. what is the concentration of the unknown h3po4 solution? the neutralization reaction is
h3po4(aq)+3naoh(aq)→3h2o(l)+na3po4( aq)

Concentration of in sample is 0.25 M.

Explanation:

From the reaction, one mole of reacts with 3 moles of NaOH.

Now, number of moles of NaOH, n =

Therefore, mol of NaOH reacts with .

So, concentration of

Therefore, concentration of in sample is 0.25 M.

Hence, this is the required solution.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j