Calculate the energy required to heat 406.0mg of cyclohexane from 33.5°c to 38.9°c .

assume the specific heat capacity of cyclohexane under these conditions is 1.85·j·g−1k−1 . x

be sure your answer has the correct number of significant digits.

We need 4.06 J to heat of 406.0 mg of cyclohexane

Explanation:

Step 1: Data given

Mass of cyclohexane = 406.0 mg = 0.406 grams

The initial temperature = 33.5 °C

The final temperature = 38.9 °C

The specific heat of cyclohexane = 1.85 J/g*K

Step 2: Calculate the energy required to heat

Q = m*c*ΔT

⇒ with m = the mass of cyclohexane = 0.406 grams

⇒ with c = the specific heat of cyclohexane = 1.85J/g*K

⇒ with ΔT = The change of temperature = T2 - T1 = 38.9 - 33.5 = 5.4

Q = 0.406 g * 1.85J/g*K * 5.40

Q = 4.06 J

We need 4.06 J to heat of 406.0 mg of cyclohexane

i believe it is 40–40–20%

explanation: