Answers: 3
is 93.8 torr
= initial pressure at 
= 23.8 torr
= final pressure at 
= ?
= enthalpy of vaporisation = 43.9 kJ/mol = 43900 J/mol
= initial temperature = 
= final temperature = 
![\log (\frac{P_2}{23.8}=\frac{43900}{2.303\times 8.314J/mole.K}[\frac{1}{298K}-\frac{1}{323K}]](/tpl/images/0470/0520/5a6d7.png)
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At 25 oc, the vapor pressure of water is 23.8 torr and the heat of vaporization is 43.9 kj/mol. calc...
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