A547-mlml sample of unknown hcl hcl solution reacts completely with na2co3na2co3 to form 17.1 gg co2co2. what was the concentration of the hclhcl solution?

the required concentration is 1.52 M

2 HCl + Na2CO3 > CO2 + H2O + NaCl

2 moles HCl reacts to form 1 mole of CO2 .

no. of moles of CO2 = 20.1/ 44.1 = 0.455

no. of moles of HCl = 0.455* 2 = 0.911 mole (molar ratio =2 from equation)

con. of HCl =no. of moles/volume in liter

=0.911/ 0.597 = 1.52 M

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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? you expect us to answer this? ? this is your schoolwork, i don't think we can with this, i think it would considering being