A0.43g sample of potassium hydrogen phthalate required 24.11cm³ naoh for neutralization. calculate the molarity of the naoh

Molarity = 0.08 M

Explanation:

Given data:

Volume of NaOH = 24.11 cm³ (24.11/1000 = 0.0241 L)

Mass of C₈H₅KO₄ = 0.43 g

Molarity of NaOH = ?

Solution:

First of all we will write the chemical equation:

C₈H₅KO₄ + NaOH  →  H₂O + KNaC₈H₄O₄

Number of moles of C₈H₅KO₄:

Number of moles  = mass/ molar mass

Number of moles = 0.43 g / 204.22 g/mol

Number of moles = 0.002 mol

Now we will compare the moles of C₈H₅KO₄ with NaOH.

                         C₈H₅KO₄          ;            NaOH

                               1                  :              1

                         0.002               :        0.002

Molarity of NaOH:

Molarity = number of moles / volume in litter

Molarity = 0.002 mol /0.0241 L

Molarity = 0.08 M

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.