If you combine 390.0 ml of water at 25.00 °c and 110.0 ml of water at 95.00 °c, what is the final temperature of the mixture? use 1.00 g/ml as the density of water.

T(final) = 40.4 °C

Explanation:

Given data:

Density of water = 1.00 g/mL

Volume of water at 25°C = 390.0 mL

Volume of water at 95°C = 110.0 mL

Final temperature of mixture = ?

Solution:

Heat absorbed by warm water = heat lost by hot water

q lost = -q lost (1)

Formula:

q = m.c.ΔT

ΔT(warm) =  T(final) - 25°C

ΔT(hot) =  T(final) - 95°C

Mass of water:

d = m/v

1 g/mL = m/ 390 mL

390 g = m

For hot water:

d = m/v

1 g/mL = m/ 110.0 mL

110.0 g = m

Now we will put the values in equation 1.

390 g. c.   (T(final) - 25°C) =  - 110.0 g .c. (T(final) - 95°C)

390 T(final) - 9750 °C = -110 T(final) + 10450 °C

390 T(final) +110 T(final) = 10450 °C +9750 °C

500 T(final) = 20200

T(final) = 20200/500

T(final) = 40.4 °C

d.) circle motion requires a force to give it a centripetal acceleration.

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .