Based on the thermodynamic properties provided for water, determine the amount of energy released for 155.0 g of water to go from 39.0 °c to -36.5°c. property melting point boiling point ahfus ahvap cp (s) value 0.0 100.0 6.01 40.67 37.1 75.3 33.6 units oc kj/mol kj/mol j/mol. oc j/mol c mol oc cp (g)

Answer : The amount of energy released will be, -88.39 kJ

Solution :

The process involved in this problem are :

The expression used will be:

where,

= heat available for the reaction = ?

m = mass of water = 155.0 g

= specific heat of solid water =

= specific heat of liquid water =

= enthalpy change for fusion =

Molar mass of water = 18 g/mole

Now put all the given values in the above expression, we get:

Therefore, the amount of energy released will be, -88.39 kJ

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

the ratio of the conjugate base to the acid required to attain the desired ph.