For the following processes, calculate the indicated quantities for a system consisting of 1 mol of n 2 gas. assume ideal gas behavior. a. t he gas, initially at 10 bar, is expanded tenfold in volume against a constant external pressure of 1 bar, all at 298 k. calculate q, w, u and h for the gas. b. a fter the expansion in part (a), the volume is fixed, and heat is added until the temperature reaches 373 k. calculate q, w, u and h. c. what will be the pressure of the gas at the end of the process in part (b)

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

the link still does not work even when adding it to the url bar

explanation: