If 120 ml of oxygen is collected over water at 27 degrees celsius & 740 mm pressure what will the volume of the dry gas be at stp

                       V₂ = 106.33 ml

Explanation:

Data Given:

                 Initial Temperature  =  T₁  =  27 °C + 273.15 = 300.15 K

                 Initial Pressure  =  P₁  =  740 mmHg

                 Initial Volume  =  V₁  =  120 ml

                 Final Temperature  =  T₂  =  0 °C + 273.15 = 273.15 K

                 Final Pressure  =  P₂  =  760 mmHg

                 Fnal Volume  =  V₂  =  ?

Formula Used:

Let's assume that the Oxygen gas is acting as an Ideal gas, the according to Ideal Gas Equation,

                       P₁ V₁ / T₁  =  P₂ V₂ / T₂

Solving for V₂,

                       V₂ = P₁ V₁ T₂/ T₁ P₂

Putting values,

                       V₂ = 740 mmHg × 120 ml × 273.15 K / 300.15 K × 760 mmHg

                       V₂ = 106.33 ml

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots