At particular temperature, kp = 70.9 for the following reactionn2o4(g) == 2no2(g)1. a certain pressure of n2o4 is initially added to an otherwise evacuated.2. at equilibrium, 25.8% of n2o4 remains.3. what is the partial pressure of no2 at equilibrium?

Answer : The partial pressure of is, 12.34  atm

Explanation :

For the given chemical reaction:

The expression of for above reaction follows:

        ........(1)

The equilibrium reaction is:

Initial             x                    0

At eqm       (x-y)                 2y

Putting values in expression 1, we get:

          ..............(2)

As we are given that, 25.8 % of remains at equilibrium. That means,

      ..............(3)

Now put equation 3 in 2, we get the value of 'x'.

Now put the value of 'x' in equation 3, we get:

Now we have to calculate the new partial pressure of at equilibrium.

Partial pressure of = (2y) = (2\times 6.17) = 12.34  atm

Hence, the partial pressure of is, 12.34  atm

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.