A20.0 l container at 303 k holds a mixture of two gases with a total pressure of 5.00 atm. if there are 1.70 mol of gas a in the mixture, how many moles of gas b are present?

moles B = 2.32 moles

Explanation:

In this case, we can assume that both gases are ideals, so we can use the expression for an ideal gas which is:

PV = nRT

From here, we can calculate the total moles (n) that are in the container, and then, by difference, we can calculate how much we have of gas B.

For this case, we will use R = 0.082 L atm / mol K. Solving for n:

n = PV/RT

n = 5 * 20 / 0.082 * 303

n = 4.02 moles

If we have 4.02 moles between the two gases, and we have 1.70 from gas A, then from gas B we simply have:

Total moles = moles A + moles B

moles B = Total moles - moles A

moles B = 4.02 - 1.70

moles B = 2.32 moles

We have 2.32 moles of gas B

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.