Asolution is formed by dissolving 36.5 g of urea, co(nh2)2, in 150.0 ml of water. what is the mole fraction of water in this solution? the density of water is 1.00 g / ml.

The mol fraction of water in this solution is 0.9319

Explanation:

Step 1: Data given

Mass of urea = 36.5 grams

Volume water = 150.0 mL

Density of water = 1.00 g/mL

Step 2: Calculate mass of water

Mass water = density * volume

Mass water = 1.00 g/mL * 150.0 mL

Mass water = 150.0 grams

Step 3: Calculate moles of water

Moles H2O = mass H2O/molar mass H2O

Moles H2O = 150.0 grams / 18.02 g/mol

Moles H2O = 8.324 moles

Step 4: Calculate moles urea

moles urea = mass urea / molar mass urea

Moles urea = 36.5 grams / 60.06 g/mol

Moles urea = 0.608 moles

Step 5: Calculate total moles

Total moles = 8.324 moles + 0.608 moles

Total moles = 8.932 moles

Step 6: Calculate mol fraction

Mol fraction of water = moles H2O / total moles

Mol fraction H2O = 8.324 moles/ 8.932 moles

Mol fraction H2O = 0.9319

The mol fraction of water in this solution is 0.9319