Write the molecular equation and the net ionic equation for the reaction of solid barium carbonate and hydrogen bromide in aqueous solution. add phase labels. (include states-of-matter under satp conditions in your answer. use the lowest possible coefficients.)

Molecular equation

BaCO3(s) + 2HBr(aq) --> BaBr2(aq) + CO2(g) + H2O(l)

Ionic equation

BaCO3(s) --> Ba2+(aq) + (CO3)2-(aq)

HBr(aq) --> H+(aq) + Br-(aq)

Resultant ionic equation

Ba2+(aq) + 2 Br-(aq) --> BaBr2(aq)

(CO3)2-(aq) + 2H+(aq) --> H2O(l) + CO2(g)

Explanation:

Molecular equation

BaCO3(s) + 2HBr(aq) --> BaBr2(aq) + CO2(g) + H2O(l)

Ionic equation

BaCO3(s) --> Ba2+(aq) + (CO3)2-(aq)

HBr(aq) --> H+(aq) + Br-(aq)

The anions bond with the cations ie the anions will give/share its outer electron while the cation accepts an electron/share its outer electron to form a stable octet in its shell a d hence a stable molecule

Ba2+ bonds with moles or Br- while (CO3)2- bonds with 2 moles of H+ and form H2O and CO2 with is given off in effervescence.

Ba2+(aq) + 2 Br-(aq) --> BaBr2(aq)

(CO3)2-(aq) + 2H+(aq) --> H2O(l) + CO2(g)

the right answer is c i just did the question.