How much heat, in calories, is given off when 1.25 grams of silver is cooled from 100.0 degrees celsius to 80 degrees celsius? (the specific heat of silver is 0.057 cal/g degrees celsius)

The heat required to raise the temperature of a certain mass of sample to a specific temperature change, we use the formula mCpΔT where m is mass, Cp is the specific heat of the substance and ΔT is the temperature change. In this case, we substitute and form 1.25 g x 0.057 cal/g C *20 C equal to 1.425 calories.

D-no effect on the rate