Astudent dissolves 15.g of styrene in 250.ml of a solvent with a density of 0.88g/ml. the student notices that the volume of the solvent does not change when the styrene dissolves in it. calculate the molarity and molality of the student's solution. round both of your answers to 2 significant digits. molarity==

The molarity and molality of styrene solution is 0.58 M and 0.66 m respectively

Explanation:

To calculate the mass of solvent, we use the equation:

Density of solvent = 0.88 g/mL

Volume of solvent = 250. mL

Putting values in above equation, we get:

To calculate the molarity of solution, we use the equation:

Given mass of styrene = 15. g

Molar mass of styrene = 104.15 g/mol

Volume of solution (solvent) = 250. mL

Putting values in above equation, we get:

To calculate the molality of solution, we use the equation:

Where,

= Given mass of solute (styrene) = 15 g

= Molar mass of solute (styrene) = 104.15 g/mol

= Mass of solvent = 220 g

Putting values in above equation, we get:

Hence, the molarity and molality of styrene solution is 0.58 M and 0.66 m respectively.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.