Ab c d 1) nanh2 2) mei 3) 9-bbn 4) h2o2, naoh 1) br2 2) excess nanh2 3) h2o 1) br2 2) excess nanh2 3) h2o 4) h2so4, h2o, hgso4 1) nanh2 2) eti 3) na, nh3 (l) e f g h 1) 9-bbn 2) h2o2, naoh 1) excess nanh2 2) h2o 3) br2 (1 eq), ccl4 1) excess nanh2 2) h2o 3) nanh2 4) mei 5) na, nh3 (l) 1) nanh2 2) 3) h2, pt

The question has some part missing which I have added in the attachment.

Explanation:

The reactions given occur under certain reagents, which we are told to pick for each of the reaction synthesis. Conventionally, halogens have the ability to undergo addition reactions with hydrocarbons by breaking down the double or triple bond in them to a single bond, this usually occur by electron donation and electron acceptor.

The attachment shows the reactions and the necessary reagents required for each

- lead + phosphoric acid = hydrogen + lead(ii) phosphate