Ascientist wants to make a solution of tribasic sodium phosphate, na3po4, for a laboratory experiment. how many grams of na3po4 will be needed to produce 615 ml of a solution that has a concentration of na ions of 0.545 m

48.38 g of Na3PO4

Explanation:

Na3PO4(s) + H2O(l) ---> 3Na+ + PO4^3-

By stoichiometry, 1 mole of Na3PO4 will dissociate in water to give 3 moles of Na+

Moles of Na+ = concentration of Na+/volume

= 0.545/615 x 10^-3

= 0.886 moles

1 mole of Na+ will be got from 0.33moles of Na3PO4

0.886 moles will be dissociated from 0.333 * 0.886 moles of Na3PO4

Moles of Na3PO4 = 0.295mol

Mass of Na3PO4 = molar mass * mass

Molecular weight = (23*3) + (31*1) + (16*4)

= 164 g/mol

Mass of Na3PO4 = 164 * 0.295

= 48.38 g of Na3PO4

the answer your looking for is c).

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