Me asap first one under 25 min gets brainlist
classification activity worksheet
instructions: read each myth (untruth). reword it to make a factual statement. then, give two to three reasons why the myth is untrue. use complete sentences and support your answer with evidence, using your own words.

1. myth: a dead organism is the same as a nonliving thing in science.
o fact:
o evidence:

2. myth: the linnaeus system of classification will always stay the same.
o fact:
o evidence:

3. myth: tigers and goldfish are not related.
o fact:
o evidence:

4. myth: an organism's kingdom only describes physical characteristics.
o fact:
o evidence:

5. myth: mammals and plants don't belong in the same domain.
o fact:
o evidence:

your turn
come up with another myth about the classification of organisms. then, give two to three reasons why the myth is untrue. use complete sentences and support your answer with evidence, using your own words.
6. your myth:
o fact:
o evidence:

You use the atomic number to find out how many protons and neutrons there are in the atom. you use the atomic mass to find out how many protons and electrons there are in the atom. 

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

The ratio is 3: 2. i.e. c.