Calculate the force of Attraction between two masses one of 5kg and one of 8kg whose center are 10 cm apart

2.67x10^-7N

Explanation:

G = 6.67×10^-11 m3/kg/s2

M1 = 5kg

M2 = 8kg

r = 10cm = 0.1m

F =?

F = GMIM2/r^2

F = (6.67×10^-11 x 5 x 8) / (0.1^2)

F = 2.67x10^-7N

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally