A toy balloon filled with air has an internal pressure of 126.625 kPa and a volume of 2500 mL. If I take the balloon to the bottom of the ocean where the pressure is 95 atmospheres, what will the new volume of the balloon be in mL?

V2 = 337646.86 mL

Explanation:

Boyle's law:

assuming constant temperature and ideal gas:

∴ V1 = 2500 mL

∴ P1 = 126.625 KPa

∴ P2 = (95 atm)×(0.009869 KPa/atm) = 0.9375 KPa

⇒ V2 = V1P1/P2

⇒ V2 = ((2500 mL)(126.625 KPa))/(0.9375 KPa)

⇒ V2 = 337646.86 mL