The specific heat of lead is 0.0380 cal/g·°C. If 47.0 calories of energy raised the temperature of a lead sample from 28.3°C to 30.1°C what is the mass of the sample?

Mass of lead, m = 687 g

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

Where,  

 is the enthalpy change

m is the mass

C is the specific heat capacity

 is the temperature change

Thus, given that:-

Mass  = ?

Specific heat = 0.0380 cal/g°C

Heat added = 47.0 calories

So,  

Mass of lead, m = 687 g

passing a magnet thought the

mixture , because iron gets attracted to magnet .