A piece of unknown metal with mass 30 g is heated to 110.0 °C and dropped into 100.0 g of water at 20.0 °C. The final temperature of the system is 25.0 °C. Determine the specific heat of the metal.

The specific heat of metal is 0.821 J/g°C

Explanation:

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

The equation used to calculate heat released or absorbed follows:

      ......(1)

where,

q = heat absorbed or released

= mass of metal = 30 g

= mass of water = 100 g

= final temperature = 25°C

= initial temperature of metal = 110°C

= initial temperature of water = 20.0°C

= specific heat of metal = ?

= specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

Hence, the specific heat of metal is 0.821 J/g°C

the answer is c. nacl