A cylindrical rod has a length of 27 cm and a diameter of 1.6 mm. What is the cross-sectional area in 10-6 m2?

The cross-sectional area of the cylindrical rod is

Explanation:

We are given a cylindrical rod whose cross-sectional area will be in the form of circle.

To calculate the area of circle, we use the equation:

where,

r = radius of the rod =    (Conversion factor: 1 m = 1000 mm)

Putting values in above equation, we get:

Hence, the cross-sectional area of the cylindrical rod is

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

b. examine and describe cells