The boiling point of ethanol is 78.4 °C, and the enthalpy change for the conversion of liquid to vapor is ΔHvap = 38.56 kJ/mol. What is the entropy change for vaporization, ΔSvap, in J/(K ⋅ mol)?

Explanation:

The given data is as follows.

    Enthalpy of vaporization, = 38.56 kJ/mol

    Temperature (T) =

                                = (78.4 + 273) K

                                = 351.4 K

Now, we will calculate the change in entropy using the formula as follows.

                       =

                       = 0.109 kJ/mol K

Thus, w ecan conclude that the entropy change for vaporization is 0.109 kJ/mol K.