If a 0.760 m aqueous solution freezes at − 3.60 ∘ C, what is the van't Hoff factor, i , of the solute?

The van't Hoff factor is 2.55

Explanation:

Step 1: Data given

molality = 0.760 molal

The aqueous solution freezes at -3.60 °C

Kb of water = 1.86°C/m

Step 2: Calculate the van't Hoff factor

ΔT = i*Kb*m

3.60 = i * 1.86 * 0.760

i = 3.60( 1.86*0.760)

i = 2.55

The van't Hoff factor is 2.55

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e