Calculate the composition, in weight percent, of an alloy that contains 218.0 kg titanium, 14.6 kg of aluminum, and 9.7 kg of vanadium.

% titanium = 89.97 %

% aluminium = 6.03 %

% vanadium = 4.00 %

Explanation:

Step 1: Data given

An alloy contains 218.0 kg titanium, 14.6 kg of aluminium and 9.7 kg of vanadium

Step 2: Calculate total mass

Total mass = mass titanium + mass aluminium + lass vanadium

Total mass = 218.0 + 14.6 + 9.7

Total mass = 242.3 kg

Step 3: Calculate weight percent

Weight percent = (mass / total mass) * 100%

% titanium = (218.0 kg / 242.3 kg)*100%

% titanium = 89.97 %

% aluminium = (14.6 kg / 242.3 kg) * 100 %

% aluminium = 6.03 %

% vanadium = (9.7 kg/ 242.3 kg) *100 %

% vanadium = 4.00 %

c. 75.7

i think that is the right

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-