Chalcocite is a mineral that contains 79.8% of copper. How many meter of wire with diameter of 0.1019 in can be produced from 5.23 lb of chalcocite?
Vcylinder = π*r2h, density of copper is 8.96 g/cm3, 1 lb=454 g

102 m

40.2 m

10.1 m

2.59 × 104

211 m

The length of copper wire that can be produced is 40.2 m

Explanation:

We are given:

Mass of chalcocite = 5.23 lb = 2374.42 g  (Conversion factor:  1 lb = 454 g)

79.8 % (m/m) of copper

This means that 79.8 grams of copper is present in 100 grams of chalcocite

Applying unitary method:

In 100 grams of chalcocite, the mass of copper present is 79.8 grams

So, in 2374.42 grams of chalcocite, the mass of copper present will be =

To calculate volume of a substance, we use the equation:

Density of copper =

Mass of copper = 1873.42 g

Putting values in above equation, we get:

To calculate the length of the wire, we use the equation:

where,

V = volume of copper wire =     (Conversion factor:   )

r = radius of the copper wire =     (Conversion factor: 1 in = 0.0254 m)

h = length/ height of the copper wire = ?

Putting values in above equation, we get:

Hence, the length of copper wire that can be produced is 40.2 m

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