A metal sphere weighing 15.45 g is added to 21.27 mL of water in a graduated cylinder. The water level rises to 24.78 mL. Calculate the density of the metal. An empty beaker weighs 32.4257 g. A 10-mL pipet sample of an unknown liquid is transferred to the beaker. The beaker weighs 40 1825 g when weighed with the liquid in it. Calculate the density of the unknown liquid.

1. Density of Metal = 4.40g/cm³

2. Density of Liquid = 0.77568g/cm³

Explanation:

1.

Given

Initial Volume of Water = Vi = 21.27mL

Volume of Water = VF = 24.78 mL

Mass of Sphere= 15.45 g

Density = Mass/Volume

Change in Volume = 24.78 - 21.27 = 3.51 mL

Density = 15.45/3.51

Density = 4.40g/ml

1ml = 1cm³

So, density = 4.40/cm³

2.

Initial Mass of Beaker = Mb = 32.4257g

Final Mass of Beaker = Mf = 40.1825 g

V = 10 mL

Density = D = ?

Change in Mass =: MF – MI= 40.1825 – 32.4257 = 7.7568 g

Density = Mass/Volume

Density = 7.7568g/10mL

Density = 0.77568g/mL

1mL = 1cm³

So, density = 0.77568g/cm³

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation: