The density at 20 ∘C of a 0.828 M solution of acetic acid in water is 1.0052 g/mL. The molar mass of acetic acid, CH3CO2H, is 60.05 g/mol. What is the molality of the solution?

Answer : The molality of solution is, 0.866 mole/kg

Explanation :

The relation between the molarity, molality and the density of the solution is,

where,

d = density of solution  = 1.0052 g/ml

m = molality of solution  = ?

M = molarity of solution  = 0.828 M = 0.828 mol/L

= molar mass of solute (acetic acid) = 60.05 g/mole

Now put all the given values in the above formula, we get  the molality of the solution.

Therefore, the molality of solution is, 0.866 mole/kg

answer; /// the amount of material dissolved in a measure of liquid(concentration) the above statement is (true); /// good luck

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.