At 450 K the rate constant is 15.4 atm-1s-1. How much time (in s) is needed for NOCl originally at a partial pressure of 56 torr to decay to 14.5 torr?

This is an incomplete question, here is a complete question.

Consider the second-order decomposition of nitroysl chloride:

At 450 K the rate constant is 15.4 atm⁻¹s⁻¹. How much time (in s) is needed for NOCl originally at a partial pressure of 53 torr to decay to 10.6 torr?

Answer : The time needed for NOCl is, 2.52 seconds.

Explanation :  Given,

Rate constant =

Initial partial pressure of NOCl = 56 torr = 0.0737 atm

final partial pressure of NOCl = 14.5 torr = 0.0191 atm

The expression used for second order kinetics is:

where,

k = rate constant

t = time

= concentration at time 't'

= initial concentration

As we know that,

Thus, the expression of second order kinetics will be:

As,

So,         ............(1)

Now put all the given values in the above expression 1, we get:

Therefore, the time needed for NOCl is, 2.52 seconds.

alchemy hadn't scientific methods of study, appeal to mysticism and fantasy, the knowledge of chemistry and physics were modest at that time.

alchemy was - but as new rules were discovered it either changed into chemistry or it became "unscientific".