An 80 kg volleyball player lands from a jump and tries to stop her forward motion. The normal contact force exerted by the floor on her shoes is 2000 N. The friction force exerted by the floor on her shoes is 600 N acting backward on the player. What is the resultant ground reaction force exerted by the floor on the volleyball player's shoes?

The answer to the question is

The resultant ground reaction force exerted by the floor on the volleyball player's shoes = 2088.06 N

Explanation:

To solve the queston we list out the variables thus

Mass of volley ball player = 80 kg

Normal force exerted on her shoes by the floor N =2000 N

friction force, f, exerted on her shoes backwards = 600 N

The resultant ground reactive force, R, is given by

R² = N² + f² = 2000² + 600² =  4000000 + 360000 = 4360000

Therefore R = √(4360000) =  2088.06 N

The direction of the force = atan (2000/600) = 73.3 ° clocwise or 106.699 ° counter clockwise