Despite the limitations of radical chlorination of alkanes, the reaction is still useful for synthesizing certain halogenated compounds. For which of the following compounds does radical monochlorination give a single product?
CH4
2-methylpropane
1-methylcyclopentane
Which one give a single product and what is radical monochlorination?

2-methylpropane

Explanation:

The structure of 2-methylpropane is contrasted with that of propane in the image attached. It is easy to see that 2-methylpropane contains a tertiary carbon atom which forms a stable radical. This stable radical formed will eventually lead to the yield of a single product which is 2-chloro-2-methylpropane. A tertiary radical is the most stable radical and often leads to the formation of a single product.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2