When the following two solutions are mixed:
K2CO3(aq) + Fe(NO3)3(aq)
the mixture contains the ions listed below.
1. Sort these species into spectator ions and ions that react.
O NO3^-(aq)
O Fe^3+(aq)
O CO3^2-(aq)
O K+(aq)

the two spectator ions are;  K(+) and NO3(-)

Explanation:

First off, let's write out the balanced chemical equation for the reaction;

3K2CO3(aq) +2Fe(NO3)3(aq) > 6KNO3(aq) + Fe2(CO3)3(s)

In order to identify which ions are spectators, we have to break the equation down to an ionic equation. This is done by splitting all aqueous compounds into ions while leaving the solids, liquids as they are.

We have;

K(+) + CO3(2-) + Fe(3+) + NO3(-) ---> K(+) + NO3(-) + Fe2(CO3)3(s)

Spectators ions are pretty much those ions that do not undergo a change in the reaction. Spectator ions always have the same number of moles and charge in both sides of the reaction.

Upon observing the ionic equation, we can tell that the two spectator ions are;  K(+) and NO3(-)

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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