A chemist prepares a solution of sodium thiosulfate (Na2S203) by measuring out 110.g of sodium thiosulfate into a 350. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's sodium thiosulfate solution. Be sure your answer has the correct number of significant digits.

1.99 M

Explanation:

The molar mass of sodium thiosulfate (solute) is 158.11 g/mol. The moles corresponding to 110 grams are:

110 g × (1 mol/158.11 g) = 0.696 mol

The volume of solution is 350 mL = 0.350 L.

The molarity of sodium thiosulfate is:

M = moles of solute / liters of solution

M = 0.696 mol / 0.350 L

M = 1.99 M

b i think it’s a water wheel turning in a stream

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml