A student is given 1.4583 g of pure CuO. To recover the Cu present in the compound, the dark powdery solid was dissolved in 15.0 mL of 6 M HCl and the solution was diluted to 50.0 mL with water. How many grams of Mg is needed to displace all of the copper (II) ions from the solution? Mg(s) + Cu2+(aq) --> Cu(s) + Mg2+(aq)

0.4402 grams of Mg is needed to displace all of the copper (II) ions from the solution.

Explanation:

Moles of CuO =

1 mole of CuO has 1 mole of ions, then 0.01834 molesof CuO will have 0.01834 moles of

According to reaction , 1 mole of copper (II) ion reacts with 1 mole of magnesium solid .

Then 0.01834 moles of copper (II) ion will react with :

of magnesium.

Mass of 0.01834 moles of magnesium :

0.01834 mol × 24 g/mol = 0.4402  g

0.4402 grams of Mg is needed to displace all of the copper (II) ions from the solution.

lol idk man i guess u gotta ask bill nye the science guy