Consider a protein with the acidic side chains, Amino Acid side-chain ArgininepKa = 12.48Aspartic Acid PKa = 3.90Cysteine pKa = 8.33Glutamic acid pKa = 4.07Histidine pKa = 6.04Lysine pKa =10.79Tyrosine pKa =10.13Given that the pH of blood is about 7.3, how many of the above side chains would be mostly in their ionic form (A-) in blood?a. 2b. 3c. 4d. 5

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter