Suppose that an element has two isotopes. The average atomic mass of the element is 45.737 u . One isotope has a mass of 40.149 u and an abundance of 37.46 % . Calculate the mass of the second isotope.

The answer to your question is 49.08 u

Explanation:

Data

Average atomic mass = 45.737 u

Isotope 1 = 40.149 u   abundance = 37.46%

Isotope 2 = ?

Process

1.- Calculate the abundance of isotope 2

abundance isotope 1 + abundance isotope 2 = 100%

                       37.46 + abundance isotope 2 = 100

                                    abundance isotope 2 = 100 - 37.46

                                     abundance isotope 2 = 62.54

2.- Calculate the mass of isotope 2

Average atomic mass = (abundance x mass isotope 1) + (abundance x

                                                                                            mass isotope 2)

45.737 = (0.3746 x 40.149) + (62.54 x mass isotope 2)

mass isotope 2 = [45.737 - (0.3746 x 40.149)]/ 62.54

mass isotope 2 = [45.737 - 15.0398]/ 62.54

mass isotope 2 = 30.6972/62.54

mass isotope 2 = 0.4908 x 100

mass isotope 2 = 49.08 u

b. examine and describe cells

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.