A rate is equal to 0.0200M/s. If [A]=0.100 M and rate= k[A]^1, what is the new rate if the concentration of [A] is increased to 0.200M?

The new rate if the concentration of [A] increased to 0.200 M is 0.0800 m/s.

Explanation:

The rate equation is r = k[a]²[b]².

Take logarithms of both sides.

ln r = ln k + 2 ln [a] + 2 ln [b]

When [a] = 0.0.100 m, r₁ = 0.0200 m/s.

Therefore

ln(0.0200) = ln k + 2 ln (0.0100) + 2 ln [b]       (1)

When a = 0.200 m, obtain the new rate, r₂, as

ln r₂ = ln k + 2 ln (0.0200) + 2 ln [b]                 (2)

Subtract (1) from (2) to obtain

ln r₂ - ln(0.0200) = 2{ln(0.0200 - ln(0.0100)} 

ln(r₂/0.0200) = 2 ln(0.0200/0.0100)

                      = 2 ln(2)

                      = ln(2²) = ln(4)

Therefore

r₂/0.0200 = 4

r₂ = 0.0800  m/s

The new rate is 0.0800 m/s.

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.

the pseudoscience are like beliefs, theories, or like practices that are considered scientific