A piece of hot metal is put into an equal mass of water. The water temperature rises 5o and the metal’s temperature drops 10o. What is the specific heat of the metal?

The answer to your question is     Cm = 2.093 J/kg°C

Explanation:

Data

mass metal = mass of water

Δ water = 5°

Δ metal = 10°

Cm = ?

Cw = 4.186 J/Kg°C

Formula

              for metal       for water

               mCmΔTm  = mCwΔTw

Cancel mass of metal

                  Cm ΔTm  =  CwΔTw

solve for Cm

                         Cm = (CwΔTw) / ΔTm

Substitution

                         Cm = (4.186 x 5) / 10

Simplification

                         Cm = 20.93 / 10

Result

                         Cm = 2.093 J/kg°C

can you attach the